Question

Read the information given below and answer the question that follows.
f(x) = x3 - 3
g(x) = (1/x) - x
What is the value of f/g, if x = 3?

Answer 1

i think your answer is..........



$- 9 \div 4$

Answer 2

The correct answer is -9.

Given: f(x) = $x^{3}-3$ and g(x) = $\frac{1}{x} -x$.

To Find: The value of $\frac{f(x)}{g(x)}$ t x = 3.

Solution:

$\frac{f(x)}{g(x)}$  at x = 3 is $\frac{f(3)}{g(3)}$.

f(x) = $x^{3}-3$

At x = 3 the value of f(x).

f(3) = $3^{3}-3$

f(3) = 27 - 3

f(3) = 24

At x = 3 the value of g(x).

g(x) = $\frac{1}{x} -x$

g(3) = $\frac{1}{3} -3$

g(3) = $\frac{1-9}{3}$

g(3) = $\frac{-8}{3}$

Now put the values of f(3) and g(3) in $\frac{f(3)}{g(3)}$.

$\frac{f(3)}{g(3)}= \frac{24}{\frac{-8}{3} }$

$\frac{f(3)}{g(3)}= \frac{24*3}{-8}$

$\frac{f(3)}{g(3)}= (-3)3$

$\frac{f(3)}{g(3)}= -9$

Hence, the value of $\frac{f(3)}{g(3)}$ is -9.

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