Math, asked by emelycansing, 1 month ago

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Answered by mathdude500
3

\huge{AηsωeR} ✍

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\bf \: \large \red{AηsωeR : 1.} ✍

Option B. Elimination

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\bf \: \large \red{AηsωeR : 2.} ✍

Option D. Substitution

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\bf \: \large \red{AηsωeR : 3.} ✍

Option B. x + y = 5 and x - y = 7

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\bf \: \large \red{AηsωeR : 4.} ✍

Option D. x + 3(2x - 9) = 8

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\bf \: \large \red{AηsωeR : 5.} ✍

Option C. 3x + 2y = 4 and 3x + 2y = - 1

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\bf \: \large \red{AηsωeR : 6.} ✍

Option D. Multiply the second equation by 4.

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Answered by adityak4m6le007
2

Answer:

  1. B. elimination
  2. D. substitution
  3. B. x + y = 5, x - y = 7
  4. D. x + 3(2x-9) = 8
  5. C. 3x + 2y = 4, 3x + 2y = -1
  6. D. Multiply the second equation by 4
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