Question

read the instructions first and answer the questions abc and d​

Answer 1

$\large\underline\purple{\bold{Solution :- }}$

Given equation of line is

$\red{ \bf \: y = 2x + 1}$

Step :- 1

When x = - 1, we get

$\tt\implies \:y \: = 2( - 1) + 1 = - 1$

Step :- 2

When x = 0, we get

$\tt\implies \:y = 2 \times 0 + 1 = 1$

Step :- 3

When x = 1, we get

$\tt\implies \:y = 2 \times 1 + 1 = 3$

Step :- 4

When x = 2, we get

$\tt\implies \:y = 2 \times 2 + 1 = 5$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf - 2 & \sf - 3 \\ \\ \sf - 1 & \sf - 1 \\ \\ \sf 0 & \sf 1\\ \\ \sf 1 & \sf 3\\ \\ \sf 2 & \sf 5 \end{array}} \\ \end{gathered}$

➢ Now the ordered pairs are (-2 , -3), (-1 , -1) , (0 , 1), (1, 3) and (2, 5).

➢ No, there is no ordered pair whose abscissa is same.

➢ Yes, its a function as there is one one Correspondence.

➢ Observations regarding the values indicates that with increase in x, there is increase in y and vice - versa.

➢The values of y is one more than twice the value of x.