Question

read the instructions first and answer the questions abc and d​

Answer 1

$\large\underline\purple{\bold{Solution :- }}$

Answer (a) and (b)

$\begin{gathered}\boxed{\begin{array}{c|c} \bf side & \bf perimeter \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 1 & \sf 4 \\ \\ \sf 2 & \sf 8 \\ \\ \sf 3 & \sf 12\\ \\ \sf 4 & \sf 16\\ \\ \sf 5 & \sf 20 \end{array}} \\ \end{gathered}$

➢ (c) To find the perimeter, we look the value of side on x - axis and corresponding value of its perimeter on y - axis.

➢ (d) Perimeter of square = 4 × side of square.

Answer 2

Step-by-step explanation:

From the given graph:-

a)Length of the side of the square =1 unit

Perimeter of a square =4 units

b) Perimeter of the square whose side 2 units =8 units

Perimeter of the square whose side 3 units =12 units

Perimeter of the square whose square 5 units =20 units

c) From the graph , On x-axis lengths of the sides are given and on y-axis Perimeters of corresponding the squares are given

The abscissa and the ordinates are like this

(1,4);(2,8);(3,12);(4,16);(5,20)...

The ordinate of the corresponding abscissa gives the Perimeter of the square

d)

From the given order pairs (1,4);(2,8);(3,12);(4,16);(5,20)...

We frame a rule given below

4=4×1

8=4×2

12=4×3

16=4×4

20=4×5

we conclude that

Perimeter of the square =4× length of its side