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Answer: (x-4)(x+1) For the 1st sum
Solving these sums is very easy
x^2-3x=4
bring 4 on the other side
x^2-3x-4 since numbers become negative
multiply the 1st and last so x^2 into 4,ans is 4
now find multiples of 4
1 into 4
2 into 2
SINCE 4-1=3
We take x^2+x-4x-4
Answer will be (x-4)(x+1)
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Answer:
Step-by-step explanation:
1. x^2 - 3x - 4 = 0
x^2 - 4x + 1x - 4 = 0
x (x - 4) + 1 (x - 4) = 0
(x + 1 )(x - 4) = 0
=P
2. x^2 + 2x + 2x +4 = 0
= x (x + 2) + 2 (x + 2) = 0
= (x + 2) (x + 2) = 0
= F
Hey, i tried solving the question which led me to a wrong word which is 'PF', sry coudnt help u out :(
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