Question

Read the paragraph carefully and write answers in Sanskrit. [02]

एवमेव पुरातनकालेडर्प अस्माकं भारत देिे एतादिा: बहव: र्वश्वर्वधालया: आसन | ति

र्वधाध्यनाय इरात देिात समागतय प्रवेिं लब्धध्वा छािा: स्वातमानं धन्यं मन्यन्ते स्म | एषुएकतम:

वलभी र्वश्वर्वधालय: | मगधराज्ये यथा नालंदा आसीत तथैव अि गुजरि प्रदेिे वलभी आसीत | अिार्प

सुदरूात देिात जना: अध्ययनाय आगच्छस्न्त स्म | अधतवे अस्मदीये गुजरि प्रदेिे वतमि ाने भावनगरे जनपदे

वलभीनामकं यदेकम उपनगरं वतिते, तिैव प्राचीनकाले वलभी र्वश्वर्वधालय: आसीत |

प्रश्ना :

1. इरात देिात छािा: ककमथि समागच्छस्न्त स्म ?

2. मगधराज्ये क: र्वश्वर्वधालय: आसीत ?​

Answer 1

Answer:

Answer:

Answer:

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Width of rectangle is 25 cm.

Step-by-step explanation:

Given :-

A wire bend in form of square of side 30 cm.

Then wire is again bend in form of rectangle of length 35 cm.

To find :-

Width of the rectangle.

Solution :-

Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape.

So,

Perimeter of square = 4 × side

⟶ Perimeter = 4 × 30

⟶ Perimeter = 120

Thus,

Perimeter of square is 120 cm.

According to concept, Perimeter of square and perimeter of rectangle are equal.

So, Perimeter of rectangle is 120 cm.

Let, Breadth or width or rectangle be x cm.

We know,

Perimeter of rectangle = 2(Length + Breadth)

⟶ 120 = 2×(35 + x)

⟶ 120 = 70 + 2x

\⟶ 120 - 70 = 2x

⟶ 50 = 2x

⟶ 50/2 = x

⟶ x = 25

We take, Width of rectangle be x.

Therefore,

Width of rectangle is 25 cm.