Chemistry, asked by kashishlike98, 2 months ago


Read the Passage given below and answer the following questions-

The group 14 elements have four electrons in outermost shell. The common oxidation states exhibited by
these elements are + 4 and +2. Carbon also exhibits negative oxidation states. Since the sum of the first
four ionization enthalpies is very high, compounds in + 4 oxidation state are generally covalent in nature.

The following questions are multiple choice questions choose the most appropriate answer.
(1) Lead compounds are stable in-
(a)+1state
(b) + 3state
(c) +4 state
(d)none of these
(2) Carbon cannot exceed its covalence more than four because-
(a) d-orbital present

.
(b) Atomic number is 6
(c) It has 3 isotopes
(d) None of these
(iii) Higher elements (of carbon group) halides undergo hydrolysis and form-
34
(a) Si F²6-
(b) [GeC6]2-
(c) (Sn(OH)6]2-
(d) a, b,c all
(iv) Complexes of higher elements of carbon group show the hybridization of the central atom is-
(a) sp3
(b) sp2
(c) sp3d1
(d) sp3d2

In heavier numbers of carbon group, the tendency :o oxidation state increase in the sequence-
(a) Ge > Sn> Pb (b) Sn<Pb < Ge (c) Sn> Pb > Ge
(d) Ge < Sn<PL​

Answers

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0

Answer:

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