Reading of ammeter A1 and A2 is respectively
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Ammeter A1 and A2 is respectively
Explanation:
- The bulb are identical so that R1 = R2 = R3 =R
- Thus, R' R/3
- According to the ohm's law V = IR
- If voltage is given 4.5 V and current pass is 3 A resistance.
- Now we substitute it as 4.5 = 3*(R/3)
- Hence the resistance power is R1 = R2 = R3 = R = 4.5 ohm's
- If we consider the two bulb work and third one get fused then it will be 2 A
- Thus here ammeter A1 shows 1, A2 = 0 B2 blow off. A2 shows 2 ampere.
Learn more: Identical, ammeter,
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