Math, asked by dhainendra527, 1 year ago

Real number x,y satisfy x^2+y^2=1. If the maximum and the minimum value of the expression z=4-y/7-x are m and m respectively, then find the value of (2m+6m)

Answers

Answered by kvnmurty
19

Answer:

4.7 approx ...  M = 161/208.    m = 10/19

Step-by-step explanation:

Given x² + y² = 1

Let x = SinФ  and y = Cos Ф.

Now  z = (4 - y) / (7 - x)

            = (4 - Sin Ф) / (7 - Cos Ф)

Differentiate wrt Ф:

dz/dФ = [ (7 - CosФ) (- cos Ф) - (4 - sin Ф) (sinФ) ] / (7 - Cos Ф)²

      = [ - 7 cos Ф + Cos² Ф - 4 SinФ + Sin² Ф ] / (7 - Cos Ф)²

      = [ 1 - 4 Sin Ф - 7 CosФ ] / (7 - Cos Ф)²

     = [ 1 - 4 y - 7 x ] / (7 - x)²

Equating it to 0 means

    4 y + 7 x = 1         ie., y = (1 - 7 x)/4

Substituting in the first equation we get:

     x² + (1 - 7 x)² /16 = 1

     16 x² + 1 + 49 x² - 14 x = 16

     65 x² - 14 x -15 = 0

      x = [7 +- √(49+65*15) ] / 65 = 39/65 or -25/65 = -5/13

      y = √(1 - x²) = +- 52/65   or  +- 12/13


d²Z/dФ² =  .....    It should be -ve for Z maximum and +ve for Z minimum.


Z = (4 - y) / (7 - x)  will be maximum when y is minimum and x is maximum.

   ie., x = 39/65, y = - 52/65

   Max Z = M = (4 + 52/65 ) / ( 7 - 39/65) = 322/416 = 161/208


Min Z = m = (4 - 12/13) / (7 + 5/13) = 40/96 = 10/19


Value of 2 M + 6 m = 2 * 161/208 + 6 * 10/19 = 4.7 approx


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Answered by Achuz5
1

Answer:


Step-by-step explanation:

Given x² + y² = 1


Let x = SinФ  and y = Cos Ф.


Now  z = (4 - y) / (7 - x)


            = (4 - Sin Ф) / (7 - Cos Ф)


Differentiate wrt Ф:


dz/dФ = [ (7 - CosФ) (- cos Ф) - (4 - sin Ф) (sinФ) ] / (7 - Cos Ф)²


      = [ - 7 cos Ф + Cos² Ф - 4 SinФ + Sin² Ф ] / (7 - Cos Ф)²


      = [ 1 - 4 Sin Ф - 7 CosФ ] / (7 - Cos Ф)²


     = [ 1 - 4 y - 7 x ] / (7 - x)²


Equating it to 0 means


    4 y + 7 x = 1         ie., y = (1 - 7 x)/4


Substituting in the first equation we get:


     x² + (1 - 7 x)² /16 = 1


     16 x² + 1 + 49 x² - 14 x = 16


     65 x² - 14 x -15 = 0


      x = [7 +- √(49+65*15) ] / 65 = 39/65 or -25/65 = -5/13


      y = √(1 - x²) = +- 52/65   or  +- 12/13



d²Z/dФ² =  .....    It should be -ve for Z maximum and +ve for Z minimum.



Z = (4 - y) / (7 - x)  will be maximum when y is minimum and x is maximum.


   ie., x = 39/65, y = - 52/65


   Max Z = M = (4 + 52/65 ) / ( 7 - 39/65) = 322/416 = 161/208



Min Z = m = (4 - 12/13) / (7 + 5/13) = 40/96 = 10/19



Value of 2 M + 6 m = 2 * 161/208 + 6 * 10/19 = 4.7 approx



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