Math, asked by mk2623, 5 hours ago

real root by bisection method of equation x^3-26

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Answered by minakshi987

Answer:

The value of the cube root of 26 rounded to 5 decimal places is 2.9625. It is the real solution of the equation x3 = 26. The cube root of 26 is expressed as ∛26 in the radical form and as (26)⅓ or (26)0.33 in the exponent form.

Answered by rlakshay037

Answer:

real root by bisection method of equation x^3-26

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real root by bisection method of equation x^3-26​

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real root by bisection method of equation x^3-26