Question

realive In (A)=5, n (AUB)= 35, n (ANB) = 8 then n (B) = ?​

Answer 1

Answer:

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

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Answer 2

Answer:

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