Really Really Important. Brainliest and thanks for the first answer.
Each time Caroline goes shopping she decides whether or not to buy fruit.
The probability that she does buy fruit is 0.7.
Independently, she then decides whether or not to buy a CD, with a probability of 0.6 that she does buy a CD.
Work out the probability that she buys fruit or buys a CD or both.
Answers
Answer:
The answer is - Caroline buys CD
Given : Each time Caroline goes shopping she decides whether or not to buy fruit.
The probability that she does buy fruit is 0.7.
Independently, she then decides whether or not to buy a CD, with a probability of 0.6 that she does buy a CD.
To Find : the probability that she buys fruit or buys a CD or both.
Solution:
P ( buy fruit ) = 0.7
P ( buy CD) = 0.6
P ( buy both) = 0.7 * 0.6 = 0.42
probability that she buys fruit or buys a CD or both.
= 0.7 + 0.6 - 0.42
= 1.3 - 0.42
= 0.88
Another method :
probability that she buys fruit or buys a CD or both. = 1 - Does not buy anything
P ( not buy fruit) = 1 - 0.7 = 0.3
P ( not buy CD) = 1 - 0.6 = 0.4
Not Buy anything = (0.3)(0.4) = 0.12
probability that she buys fruit or buys a CD or both. = 1 - 0.12 = 0.88
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