Question

Really.. These geometries.. Need some help btw

Answer 1

HEYA MATE, HERE IS UR ANSWER ___________________

Angle P +Angle BAC=180 ( PBAC is a cyclic quadrilateral. )

Angle Q+angle ABC=180 ( QABC is a cyclic quadrilateral )

angle R+angle ACB=180 (RACB is a cyclic quadrilateral )

Angle P +Angle Q+angle R +angle BAC+angle ABC +angle ACB

= P+BAC+Q+ABC+R+ACB

=180+180+180

=540 _______(1)

Angle P+angle Q+angle R

From eq 1.

P+Q+R+ABC+BAC +ACB =540

P+Q+R=540-ABC -BAC-ACB.


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