Question

rearrange suitably and add -3/7+5/6+4/7+1/3+13/-6

Answer 1

Answer:

$\frac{-6}{7}$

Step-by-step explanation:

1) We have,

The expression:

$\frac{-3}{7}+\frac{5}{6}+\frac{4}{7}+\frac{1}{3}+\frac{13}{-6}\\ \\= [\frac{-3}{7}+\frac{4}{7}]+[\frac{5}{6}+\frac{1*2}{3*2}]-\frac{13}{6}\\ \\= [\frac{-3}{7}+\frac{4}{7}]+[\frac{5}{6}+\frac{2}{6}]-\frac{13}{6}\\ \\== [\frac{4-3}{7}]+[\frac{5+2}{6}]-\frac{13}{6}\\ \\=[\frac{1}{7}]+[\frac{7}{6}]-\frac{13}{6}\\ \\=[\frac{1}{7}]+[\frac{7-13}{6}]\\ \\=[\frac{1}{7}]+[\frac{-6}{6}]\\ \\=\frac{1}{7}-1\\ \\=\frac{-6}{7}$

2) Hence, Required Value of expression is -6/7.

Answer 2

Step-by-step explanation:

ans:

(12;())_3())"48)#!+*

zhmmsiikz&-28))₹++(*(

s++38()#-())₹++("()₹

+((39)2))={{`}%}

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