Question

rearrange suitably and find the sum 3upon5+ 7upon3+ -4upon 15 +( -4)​

Answer 1

Answer♡~

$\large \frac{3}{5} + \frac{7}{3} + \frac{ (- 4)}{15} + ( - 4)$

First take the L.C.M. to make the denominators same.

L.C.M. of 5, 3,15= 15

$\implies \frac{3}{5} \times \frac{3}{3} = \frac{9}{15} \\ \\ \implies \frac{7}{3} \times \frac{5}{5} = \frac{35}{15} \\ \\ \implies \frac{ - 4}{15} \times \frac{1}{1} = \frac{ - 4}{15} \\ \\ \implies \frac{ - 4}{1} \times \frac{15}{15} = \frac{ - 60}{15} \\ \\ \rightarrow\frac{9 + 35 + ( - 4) + ( - 60)}{15} \\ \\ \rightarrow \frac{ 9 + 35 - 4 - 60}{15} = \cancel\frac{ - 20}{15} = \frac{ - 4}{3}$

☺Hope it helps you.....

Answer 2

Answer:

• Ur question :

Rearrange suitably and find the sum

$\frac{3}{5} + \frac{7}{3} + \frac{ - 4}{15} + ( - 4)$

• Solution :

First we have to find out the LCM to make the denominators same.

LCM of 5, 3, 15 = 15

So now we now the LCM

Now we proceed

$\frac{3}{5} + \frac{7}{3} + \frac{ - 4}{15} + ( - 4) \\ \\ \implies \frac{3}{5} \times \frac{3}{3} = \frac{9}{15} \\ \\ \implies \frac{7}{3} \times \frac{5}{5} = \frac{35}{15} \\ \\ \implies \frac{ - 4}{15} \times \frac{1}{1} = \frac{ - 4}{15} \\ \\ \implies\frac{ - 4}{1} \times \frac{15}{15} = \frac{ - 60}{15} \\ \\ \implies \frac{9 + 35 + ( - 4) + ( - 60)}{15} \\ \\ \implies \frac{9 + 35 - 4 - 60}{15} = \frac{ - 20}{15} = \frac{ - 4}{3}$