Question

rearrange w=3(2a+b)-4 to make a the subject

Answer 1

Answer:

Step-by-step explanation:

What is being done will be written in brackets on the right

w = 3(2a+b)-4                            

w + 4  = 3(2a+b)                         [4 is added on both sides of the equation]

w + 4 = 6a + 3b                          [the brackets on the right is expanded]

w + 4 - 3b = 6a                           [3b is subtracted on both sides of the equation]

w/6 + 4/6 - 3b/6 = a                   [both sides are divided by 6]

a = w/6 +2/3 - b/2

Answer 2

Answer:

The answer is $a=\frac{w+4-3 b}{6}$.

Step-by-step explanation:

Given:

$w=3(2a+b)-4$

To make a subject of the above equation.

Step 1

Add $4$ to both sides of the above equation,

$3(2 a+b)-4+4=w+4$

Simplifying the above equation

$3(2 a+b)=w+4$

Divide both sides by $3$, we get

$\frac{3(2 a+b)}{3}=\frac{w}{3}+\frac{4}{3}$

then the equation will be

$2 a+b=\frac{w+4}{3}$

Step 2

Subtract $b$ from both sides of the equation

$2 a+b-b=\frac{w+4}{3}-b$

Simplify

$2 a=\frac{w+4}{3}-b$

Divide both sides by $2$

$\frac{2 a}{2}=\frac{\frac{w+4}{3}}{2}-\frac{b}{2}$

Simplify

$a=\frac{w+4-3 b}{6}$

Therefore, the answer is

$a=\frac{w+4-3 b}{6}$.

#SPJ2