Question

reasinnig 128,,,,32,,,.?.

Answer 1

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Mention:-

17 replace 71

ACCORDING TO THE QUESTION...

13 19
∆
4

$<b>Step:-1 Prove First terms...<b>$

$<b>Adding upper Side=13+19=32<b>$

Now...

Divided by Last terms
=32÷4=8

$<b>Here....<b>$

8×4=32

$<b>Second terms....<b>$

17 9
∆
10

$<b>Adding both upper terms=71+9=80<b>$

$<b>As per as first terms<b>$

Divided 80 by 8

=80/8
=10

$<b>As per as QUESTION Solving Required terms..<b>$

128 32
∆
?

Now..

Adding both upper terms..

128+32=160

Divided 160 by 8

=160/8
=20

$<b>Answer:-20<b>$