recall that two circles are congruent if they have the same radii prove that equal chords of congruent circle subtend equal equal angles and their centres
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proved that equal chords of congruent circle subtend equal equal angles at their centres
Step-by-step explanation:
Let say there are two congruent circle with cenetr A & P
Radius of circle is same as congruent circle
let say BC & QR are Equal Chords
Then if we compare ΔABC & ΔPQR
AB = PQ ( radius)
AC = PR ( radius)
BC = QR ( equal chord given)
=> ΔABC ≅ ΔPQR
=> ∠BAC = ∠QPR
These are the angles subtended by chord at center
Hence proved that equal chords of congruent circle subtend equal equal angles at their centres
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