Recall that two circles are congruent if they have the same radii. Prove that equal
chords of congruent circles subtend equal angles at their centres.
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Step-by-step explanation:
Given:- C(O,r) and C₁(O₁,r₁), where r=r₁ and PQ=AB
To prove:- ∠AOB=∠PO₁Q
Solution:- In ΔAOB and ΔPO₁Q,
AB=PQ(given)
AO=PO₁(since radii are equal)
OB=O₁Q(")
⇒ΔAOB≅ΔPO₁Q
∴ By CPCT, ∠AOB=∠PO₁Q
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