Question

Record the following transactions in the purchase book of Dileep:
2000
Feb. 1. Bought from Ramlal and Sons 50 Sarees @ Rs. 7 each and 40 mts. of shirting
for Rs. 400.
Feb. 15 Purchased from Satish Chandra and Bros. :
20 mts. coating @ Rs. 30 per mt.
40 pairs of dhoti @ Rs. 9 per pair.
50 mts. of shirting for Rs. 740 (Trade discount 5%)​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.