Math, asked by vivekom000, 11 months ago

rect I
and the perimeter of the
6 cm​

Answers

Answered by Shivamyadav4131
1

Answer:

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Step-by-step explanation:

please post complete question my friend

Answered by Anonymous
1

\huge\bf\red{ɢɪᴠᴇɴ :}

ᴛʜᴇ ʙᴀꜱᴇ ᴏꜰ ᴛʜᴇ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ ɪꜱ ᴛʜʀɪᴄᴇ ɪᴛꜱ ʜᴇɪɢʜᴛ.

ᴀʀᴇᴀ ᴏꜰ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ = 867 ᴄᴍ²

\huge\bf\red{Tᴏ Fɪɴᴅ :}

ᴛʜᴇ ʜᴇɪɢʜᴛ.

ᴛʜᴇ ʙᴀꜱᴇ.

\huge\bf\red{Sᴏʟᴜᴛɪᴏɴ : }

ʜᴇɴᴄᴇ,ɪᴛ ɪꜱ ɢɪᴠᴇɴ ᴛʜᴀᴛ ᴛʜᴇ ʙᴀꜱᴇ ᴏꜰ ᴛʜᴇ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ ɪꜱ ᴛʜʀɪᴄᴇ ɪᴛꜱ ʜᴇɪɢʜᴛ.

ʟᴇᴛ'ꜱ ꜰɪʀꜱᴛ ᴄᴏɴꜱɪᴅᴇʀ ᴛʜᴇ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʜᴇ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ ʙᴇ x ᴛʜᴇɴ ᴛʜᴇ ʙᴀꜱᴇ ᴡɪʟʟ ʙᴇ 3×x = 3x

Now,

{\underline{\boxed{\sf{\blue{Area_{(parallelogram)}=base\times{height}}}}}}

\dashrightarrow\sf{867=3x\times{x}}

\dashrightarrow\sf{867=3x^2}

\dashrightarrow\dfrac{\cancel{867}^{289}}{\cancel{3}^1}\sf{=x^2}

\dashrightarrow\sf{289=x^2}

\dashrightarrow\sf{x=\sqrt{289}}

\dashrightarrow\sf{x=\sqrt{17\times{17}}}

\bigstar\underline{\boxed{\sf{\pink{x=17}}}}

{\text{\sf{Therefore,the Height (x) is 17cm}}}

{\text{\sf{And the Base (3x)}}}\sf{= 3\times{17}=51 cm.}

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