Question

rectangle ABCD is a rhombus .Hence prove that sum of squares of side of this rhombus is equal to the sum of squares of its diagonal​

Answer 1

Answer:

Given :- A rhombus ABCD whosediagonals AC and BD intersect at O. ToProve :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that thediagonals of a rhombus bisect each other at right angles. ... [ In a rhombus , all sides are equal ] .