Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A (2,0) B (6,) C(6,7) D(2,7)
What is the area of rectangle ABCD

Answer 1

asss per the question this is the graph

area of rectangle - l × b

here l = 7 unit

b = 4 unit

so

7×4 =28

Answer 2

Answer:

The final answer is  $4\sqrt{65}$

Step-by-step explanation:

Before doing this problem, We need to remember two basic concepts. First a rectangle has two equal sides. Secondly, The area of a rectangle = l * b.

Next we need to find the length and breadth of the rectangle and we need to find only the magnitude of two sides.

We need to apply the formula

$\sqrt{(x1^-x2)^2 +(y2-y1)^2}$

First we take AC then,

x1 =2    y1 = 0

x2 = 6   y2 =7

By applying the formula,

$\sqrt{(2-6)^2 + (7-0)^2 }$

$\sqrt{16+49}$

$\sqrt{65}$

Next we take CD

x1 = 6     y1 = 7

x2 = 2     y2 = 7

By applying the formula,

$\sqrt{(6-2)^2+(7-7)^2}\\\\ \sqrt(16)\\\\4$

Area of rectangle = l * b = $4\sqrt{65}$

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