Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -6), B(5, -6), C(5, -2), D(2, -2)
What is the perimeter of rectangle ABCD?

Answer 1

Answer:

Perimeter of rectangle = 14

Step-by-step explanation:

Given, vertices of rectangle A = (2,-6),

B = (5,-6), C = (5,-2), D = (2,-2)

AB={(5-2)^2 + ((-6) - (-6))^2}^1/2 = {9+0}^1/2 = 3

BC= {(5-5)^2 + ((-2) - (-6))^2}^1/2 = {0+16}^1/2 = 4

CD = {(2-5)^2 + ((-2) - (-2))^2}^1/2 = {9+0}^1/2 = 3

DA = {(2-2)^2 + ((-2) - (-6))^2}^1/2 = {0+16}^1/2 = 4

So AB = CD = 3 and BC = AD = 4

Length = 4 and width = 3

Perimeter of rectangle = 2(length+width)

= 2(4+3)

= 2 * 7

= 14