Question

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-8, 3)A(−8,3)A, left parenthesis, minus, 8, comma, 3, right parenthesis, B(-3, 3)B(−3,3)B, left parenthesis, minus, 3, comma, 3, right parenthesis, C(-3, 6)C(−3,6)C, left parenthesis, minus, 3, comma, 6, right parenthesis, and D(-8, 6)D(−8,6)D, left parenthesis, minus, 8, comma, 6, right parenthesis. What is the area of rectangle ABCDABCDA, B, C, D?

Answer 1

Complete question: Rectangle $ABCD$ is graphed in the coordinate plane. The following are the vertices of the rectangle: $A\:(-8,\:3)$, $B\:(-3,\:3)$, $C\:(-3,\:6)$ and $D\:(-8,\:6)$.

To find: We have to find the area of the rectangle $ABCD$.

Solution:

The vertices of the rectangle $ABCD$ are $A\:(-8,\:3)$, $B\:(-3,\:3)$, $C\:(-3,\:6)$ and $D\:(-8,\:6)$.

We see that the side $AB$ is its length and $BC$ is its width.

Finding the length and the width of the given rectangle:

Length.

• Length of the side $AB$ is
• $=\sqrt{(-3+8)^{2}+(3-3)^{2}}$ units
• $=\sqrt{25+0}$ units
• $=\sqrt{25}$ units
• $=5$ units

Width.

• Length of the side $BC$ is
• $=\sqrt{(-3+3)^{2}+(6-3)^{2}}$ units
• $=\sqrt{0+9}$ units
• $=\sqrt{9}$ units
• $=3$ units

Finding the area of the given rectangle:

$\therefore$ the area of the rectangle $ABCD$ is

$\quad\quad=5\times 3$ sq. units

$\quad\quad=15$ sq. units .

Answer 2

Answer:

15

Step-by-step explanation:

RIGHT?