Question

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -3),A(2,−3),A, left parenthesis, 2, comma, minus, 3, right parenthesis, comma B(4, -3)B(4,−3)B, left parenthesis, 4, comma, minus, 3, right parenthesis, C(4, 5)C(4,5)C, left parenthesis, 4, comma, 5, right parenthesis, and D(2, 5)D(2,5)D, left parenthesis, 2, comma, 5, right parenthesis. What is the perimeter of rectangle ABCD?

Answer 1

Answer:

Peremeter 20

Area 18

Step-by-step explanation:

“…K…”

Answer 2

Therefore the perimeter of the rectangle ABCD is 20 units.

Given:

Vertices of the rectangle:

A - ( 2, -3 )

B - ( 4, -3 )

C - ( 4, 5 )

D - ( 2, 5 )

To Find:

The perimeter of the rectangle ABCD.

Solution:

The given question can be solved as shown below.

Length of AB = √(4-2)² + (-3 - (-3))² = 2 units

Length of BC = √(4-4)² + (5 - (-3))² = 8 units

Length of CD = √(2-4)² + (5 - 5)² = 2 units

Length of DA = √(2-2)² + (5 + 3 )² = 8 units

So length of the rectangle = l = 8 units

Breadth of the rectangle = b = 2 units

Perimeter of the rectangle = 2( l + b )

⇒ Perimeter of the rectangle = 2 ( 8 + 2 ) = 20 units

Therefore the perimeter of the rectangle ABCD is 20 units.

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