Question

rectangle has length which is 5 cm less than twice its breadth if the length is decreased by 5 cm and the breadth is increased by 2 centimetre the perimeter of the resulting rectangle will be 74 cm find the length and the breadth of the original rectangle

Answer 1

Length of the original rectangle = 2b-5
Length of the new rectangle =2b-5-5=2b-10
Breadth of the new rectangle=b+2
Perimeter of the new rectangle= 74
2(2b-10+b+2)=74
2b(3b-8)=74
6b-16=74
6b=90
b=15
length =2b-5
=2×15-5
25

Answer 2

given:
original length and breadth,
let breadth (b)=x cm
length (l)=2x-5
second length and breadth,
l=2x-5-5
b=x+2

To find:
original length and breadth

solution:
perimeter=2(l+b)
ACQ,
2[(2x-5-5)+(x+2)]=74
2(2x-10+x+2)=74
3x-8=74/2=37
3x=37+8
x=45/3
x=15cm
therefore, original length and breadth are;
l=2x-5
=2(15)-5
=25cm
b=x
=15cm