Question

Rectangle is 16metre by 9 metre find the side of a square whose area is equal to the area of rectangle by how much does the perimeter of the rectangle exceeds the perimeter of square

Answer 1

area of rectangle =l*b=16×9=144sq.m
area of square =144sq.m
side of square =
$\sqrt{144}$
=12m
perimeter of square = 12×4=48m
perimeter of rectangle =2(16+9) = 50m
50m-48m=2m