Question

Rectangle's length is 8cm larger than it's width. Calculate the sides of the rectangle if its area is 65 cm^2

Answer 1

Answer:

Let the width of rectangle be x

Length is 8 cm larger than width=x+8

Area of rectangle=l*b

=x(x+8)=65

x^2+8x-65=0

x^2+13x-5x-65=0

x(x+13)-5(x+13)=0

(x-5)(x+13)=0

x=5,-13

width=5cm

length=x+8

=5+8

=13cm

Answer 2

Answer:

L=13cm,B=5cm.

Step-by-step explanation:

Let the width(breadth) be x cm.

Then the length is x+8 cm.

Area = L×B.

65 = x(x+8)

65 = x²+8x

x²+8x-65=0

x²-5x+13x-65=0. (Middle Term Splitting)

x(x-5)+13(x-5) =0

(x+13)(x-5)=0

x+13=0. or. x-5=0.

x=-13. or. x=5.

x=5cm. (-13 will be eliminated bcuz length or

breadth cannot be -ve)

So, Breadth=5cm and Length = 5+8 = 13cm.

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