Math, asked by jawadys, 9 months ago

rectangular coil has a cross-sectional area of 30 cm2 and 50 turns. If the coil rotates at 60 rad/s in a magnetic field of 0.2 Wb/m2 such that its axis of rotation is perpendicular to the direction of the field, determine the induced emf in the coil.

Answers

Answered by tiwariakdi
0

The induced emf is 3.6π volts.

  • It is the creation of a potential difference in a coil as a result of variations in the magnetic flux flowing through it. To put it another way, it is said that electromotive force, or EMF, is created when the flux connecting with a conductor or coil changes.
  • The first method entails positioning an electric conductor in a fluctuating magnetic field. The second method entails positioning a conductor that is constantly moving in a magnetic field that is static in nature. It is employed in galvanometers, transformers, and generators, among other places. Induced emf also has other uses.

Here, according to the given information, we know that,

w = 2\pi f=2\pi (60) = 120\pi

Area = 30 cm^{2} =0.003 m^{2}.

Therefore, induced voltage = V= NABw=50.(0.003).(0.2).120\pi =3.6\pi.

Hence, the induced emf is 3.6π volts.

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