Question

Rectangular container with base 8cm by 5 cm contains some water. When a cube of edge 4 cm is placed in it the water level rises. Find the rise in the water level

Answer 1

$perimeter \: of \: rectangular \: container = l \times b \\ 8 \times 5 \\ 40 \\ volume \: of \: cube = (side) {}^{3} \\ 4 {}^{3} \\ 64 \\ therefore \: f \\ the \: rise \: of \: containment \: tank = 40 \times 64 \\ = 2560$

Answer 2

The rise in water level is 1.6 cm.

Step-by-step explanation:

Consider the provided information.

Rectangular container with base 8cm by 5 cm contains some water.

When a cube of edge 4 cm is placed in it the water level rises.

The volume of Cube = a³

The volume of Cube = 4³ = 64 cm³

Now we need to find the rise in water level.

$5\times8\times h=64\\\\h=\frac{8}{5}\\\\h=1.6$

Hence, the rise in water level is 1.6 cm.

#Learn more

100men took a dip in a pond 50m long and 18m wide .If the average displacement of water by a men was 3.6 m cube then calculate the rise in the water level​

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