rectangular garden is 115 m by 90 m. It has two roads, each 6m wide, running in middle of it, one parallel to its length and other parallel to its breadth. Find the cost of constructing the roads at 100 per m².
Answers
Answer:
117900
Step by step explanation:
Area covered by path running parallel to length = Width x Length
= 6 x 115 m^2
= 675 m^2
Area covered by path running parallel to breadth = Width x Length
= 6 x 90 m^2
= 540 m^2
But since both the roads must intersect at a place within the garden, we must subtract the area of that place so that we don't repeat it.
The area of this place will be 6 x 6 m^2 since the width of both the roads is 6m.
Therefore the area covered by both the roads = (675 + 540 - 36) m ^2
= 1179 m^2
Since the cost of constructing roads is 100/m^2, the total cost for constructing these roads = 100 x 1179 m^2
= 117900
Hope this helps
THEN, CE=54cm2/7.5 =7.2 cm Ans
Answer:
Ce=7.5 cm
Step-by-step explanation:
hope this is heloful
