rectangular glass slab is kept at the the bottom of through containing water a light ray is incident on water surface at an angle of 45 degree and it passes through water into glass if the refractive index of water is 4/3 and that for the glass is 3/2 find the angle of refraction in glass
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Refractive index of a rectangular glass slab is m=3 . A light ray incident at an angle 60∘is displaced laterally through 2.5cm. Distance traveled by light in the slab is :
A
4 cm
B
5 cm
C
2.53 cm
D
3 cm
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ANSWER
Given μ=3
θa=600
Lateral shift d=tcosθb′sin(θa−θb′) ...................(1)
Let the length traveled in glass be l.
From geometry, t=lcosθb′ ..........................(2)
Substituting t from (2) in (1)
d=lsin(θa−θb′) .............................................(3)
From Snell's law, sinθb′sinθa=μ
⇒sin600=3sinθb′
⇒sinθb′=21
⇒θ
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