rectangular paper of length 66cm and breadth 14 cm is rolled into a cylinder along the length. Find the total surface area and volume
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Given rectangular sheet of paper is rolled along its breadth length = 28 cm breadth = 22 cm Hence height of cylinder, h = 28 Circumference of the base of cylinder = 2πr = 22 cm 2 × (22/7) × r = 22 Therefore, r = 7/2 = 3.5 cm Volume of cylinder = πr2h = (22/7) × (3.5)2 × 28 = 1078 cu cm Thus the volume of the cylinder is 1078 cu cm.
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Answer:
Given,
length=height = 66cm
Breadth = diameter = 14 cm
Radius =14/2 = 7 cm
TSA(Total surface area of a cylinder ) = 2"r(r+h)
2x22/7 x 7(7+66)
44x73=3212cm*2
volume of a cylinder = "r*2h
22/7x7x7x66=10,164cm*3
*TSA ( Total surface area of a cylinder ) =3212 cm*2
*volume of the cylinder = 10,164cm*3
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