Math, asked by rajrdx, 1 year ago

rectangular park of length=70m and breath=62 square park of side =80m
(1) who cover more distance?
(2) which of the above has less area?

Answers

Answered by kittu9876
16
p of rect. = 2*( l+b )
= 2×( 70+62)
= 2×132
=264
p of squ. = 4s
4× 80
= 320

area of rect.= l×b
= 70×62
= 4340
area of squ.= s×s
= 80×80
=640


a). squ. cover more didtance
b).rect. covers more area

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kittu9876: welx
ppp54: i think 80x80=6400
Kittu1298: yeah by mistake sry...
Kittu1298: mark it as brainlist
Answered by duragpalsingh
37
Hey there! ☺☻☺

Given,
Dimensions of rect. park :
Length = 70 m; Breadth = 62 m
Dimensions of square park:
Side = 80 m

1) Distance = Perimeter
Perimeter of rect = 2(l+b)
                            = 2(70+62)
                            = 2*132
                            = 264 m
Perimeter of square = 4 * side
                                 = 4 * 80
                                 = 320 m

Hence, Square park cover more distance i.e 320 m.

2) Area of rect. = l*b = 70 * 62 = 4340 m²
   Area of square = side² = (80)² = 6400 m²
Hence, Rectangular park has less area.

Hope It Helps You! ☺☻☺

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