Question

Rectangular plot measuring 90 metres by 50 metres needs to be enclosed by wire fencing such that poles of the fence will be kept 5 metres apart. How many poles will be needed?​

Answer 1

First, we need to find the perimeter which is 2 X (l+b)
=2 X (90+50)m
=2 X 140m
=280m
Since we’ve been asked to find the number of poles which are 5 metres apart, we’ll divide it by 5
280m divided by 5 is 56m
So the answer is 56m

Answer 2

Answer:

56 poles will be needed.

Solution:

Length of the wire fencing:

Given,

Length = 90 m

Breadth = 50 m

By using the formula of Perimeter of Rectangle.

Perimeter of Rectangle = 2 × (l + b)

=> 2 × (l + b)

Now, putting the given values.

=> 2 × (90 + 50)

=> 2 × 140

=> 280 m

Poles of the fence will be kept 5 metres apart, the poles will be placed along the perimeter of the rectangular plot.

Hence,

Number of poles required = 280 / 5 = 56

.°. Number of poles required = 56 poles.