rectangular room of size 5 mm x 35 cm is to be ka carpented with the carpet 70 m wide find the length of the required
with correct statement
Answers
Answer:
Given:
A rectangular room of size 5 dm * 35 dm is to carpeted with a carpet 7 dm wide.
\sf{\Large{\underline{\sf{To\:find\::}}}}
Tofind:
The length of the carpet.
\bf{\Large{\underline{\underline{\tt{\red{Explanation\::}}}}}}
Explanation:
Using formula of the area of rectangle:
\boxed{\sf{\red{Area\:of\:rectangle\:=\:Length*Breadth}}}}
\begin{gathered}\bf{\pink{Given}\begin{cases}\sf{Length\:(L)\:=\:5m}\\ \sf{Breadth\:(D)\:=\:35dm=3.5m}\\ \sf{Width\:(W)\:=\:7dm=0.7m}\end{cases}}\end{gathered}
Given
⎩
⎪
⎪
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⎪
⎪
⎧
Length(L)=5m
Breadth(D)=35dm=3.5m
Width(W)=7dm=0.7m
A/q
\begin{gathered}|\implies\sf{Area\:of\:rectangular\:room\:=\:5 m*3.5m}\\\\\\\\|\implies\sf{\red{Area\:of\:rectangular\:room\:=\:17.5m^{2}} }\\\\\\\\Now,\\\\\\|\implies\sf{Length\:of\:the\:carpet\:=\:\dfrac{Area\:of\:rectangular\:room}{Width\:of\:carpet} }\\\\\\\\|\implies\sf{Length\:of\:the\:carpet\:=\:\cancel{\dfrac{17.5}{0.7}} m}\\\\\\\\|\implies\sf{\red{Length\:of\:the\:carpet\:=\:25m}}\end{gathered}
∣⟹Areaofrectangularroom=5m∗3.5m
∣⟹Areaofrectangularroom=17.5m
2
Now,
∣⟹Lengthofthecarpet=
Widthofcarpet
Areaofrectangularroom
∣⟹Lengthofthecarpet=
0.7
17.5
m
∣⟹Lengthofthecarpet=25m