Question

rectangular sheet of length 30 cm and 3 cm is kept on a principal axis of a concave mirror of focal length 30 cm draw the image formed by the mirror on the same diagram as far as possible on the scale​

Answer 1

Explanation:

Here,

u= -30 cm

f= -20 cm

By using mirror formula,

1/v + 1/u = 1/f

1/v + 1/-30 = 1/-20

v= -60 cm

negative sign indicates that image is in front of the mirror

Therefore,

The distance between image and object = 60–30 = 30cm

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Answer 2

Given that,

Focal length = -30 cm

Object distance = 30 cm

Length = 30 cm

We need to calculate the image distance

Using formula of mirror

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Where, f = focal length

v = image distance

u = object distance

Put the value into the formula

$\dfrac{1}{-30}=\dfrac{1}{v}-\dfrac{1}{-30}$

$\dfrac{1}{v}=\dfrac{1}{-30}-\dfrac{1}{30}$

$v= -15\ cm$

We need to calculate the height of image

Using formula of magnification

$m=\dfrac{v}{u}=\dfrac{h_{i}}{h_{o}}$

Put the value into the formula

$\dfrac{-15}{-30}=\dfrac{h_{i}}{30}$

$h_{i}=15\ cm$

The length of image is 15 cm.

Hence, The image distance is 15 cm from the mirror in left side.