Question

Rectangular tiles each of size 70 cm by 30 cm must be laid horizontally on a rectangular floor of size 110 cm by 130 cm, such that the tiles do not overlap. a tile can be placed in any orientation so long as its edges are parallel to the edges of the floor. no tile should overshoot any edge of the floor. the maximum number of tiles that can be accommodated on the floor is

Answer 1

(130*110)/(70*30)=6.8 so max no of tiles will be 6.

Answer 2

Given:

The dimensions of the rectangular tiles = 70 cm by 30 cm

The dimensions of the rectangular floor = 110 cm by 130 cm,

To Find:

The maximum number of tiles that can be accommodated on the floor

Solution:

The maximum number of tiles that can be accommodated on the floor is 6.

Since the horizontal floor is to be covered by the maximum number of rectangular tiles while avoiding overlapping,

We can find the number of tiles required to cover the area by dividing the area of the floor into rectangles each having area equal to the area of a tile.

Area of the tile = 70 × 30 = 2100 cm²

Area of floor = 130 × 110 = 14300 cm²

No of tiles required to cover the entire floor = 14300 / 2100

= 143 / 21

= 6.8

Since no overlapping is to be done, the maximum number of tiles that can be accommodated is 6.