Question

Red queens and black jacks are removed from a pack of 52 playing cards find tge probability of a card of club or an ace

Answer 1

number of red Queens in the cards = 1+1

= 2

number of black jacks = 1+1

= 2

therefore, number of cards obtained by removing red Queens and black jacks will be = 52 - (2+2)

= 48

let the probability of finding a card of club or an ace be

P(E)

number of clubs = 13 - 1

= 12

number of ace Cards are = 4

number of clubs and ace Card

so now probability P(E) = _______________________

number of cards

12 + 4

P(E) = ______

48

P(E) = 16/48

P(E) = 1 / 3 is your answer..

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