Chemistry, asked by aryah, 1 year ago

reddish brown deposits formed on iron nails kept in a solution of copper sulphate is

Answers

Answered by DharshiniK
57
Through Displacement Reaction
Fe + CuSO4-> FeSo4+ Cu
Therefore the reddish brown deposit is Cu deposits
Answered by qwvampires
1

Reddish brown deposits formed on iron nails kept in a solution of copper sulphate is displacement reaction.

Fe + CuSO₄ -> FeSO₄ + Cu

  • The reddish-brown layer formed on iron nails is called rust. Rusting of iron is caused due to oxidation of iron.
  • When iron nails are placed in the open air for long periods or in a humid environment, oxygen present in the air combines with iron atoms to form Fe₂O₃.nH₂O.
  • Iron is more reactive than copper. Copper is one of the least reactive metals along with gold and silver.
  • Copper sulfate has ions of SO₄⁻. Iron tries to react with the SO₄⁻ ions present in the solution to form FeSO₄. This leads to the accumulation of Cu⁺ ions in the solution. They settle on the surface of the nails.
  • This is an example of displacement reaction because Fe displaces Cu from the solution to form FeSO₄.
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