reddish brown deposits formed on iron nails kept in a solution of copper sulphate is
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Through Displacement Reaction
Fe + CuSO4-> FeSo4+ Cu
Therefore the reddish brown deposit is Cu deposits
Fe + CuSO4-> FeSo4+ Cu
Therefore the reddish brown deposit is Cu deposits
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Reddish brown deposits formed on iron nails kept in a solution of copper sulphate is displacement reaction.
Fe + CuSO₄ -> FeSO₄ + Cu
- The reddish-brown layer formed on iron nails is called rust. Rusting of iron is caused due to oxidation of iron.
- When iron nails are placed in the open air for long periods or in a humid environment, oxygen present in the air combines with iron atoms to form Fe₂O₃.nH₂O.
- Iron is more reactive than copper. Copper is one of the least reactive metals along with gold and silver.
- Copper sulfate has ions of SO₄⁻. Iron tries to react with the SO₄⁻ ions present in the solution to form FeSO₄. This leads to the accumulation of Cu⁺ ions in the solution. They settle on the surface of the nails.
- This is an example of displacement reaction because Fe displaces Cu from the solution to form FeSO₄.
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