Redefine the above function
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- f(x)=[x-2]+[2+x],-3<_x<_3 =>[x-2]+[x+2] =0 =>[(x(x+2)-2(x+2)] =0 =>x^2+2x-2x-4 =0 =>x^2=4 =>x=+-√4=+-2
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வணக்கம் நண்பா. Follow back pannunga
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