Question

redefine the function which is given by
f(x)=|x-1|+|1+x|,-2<=x<=2​

Answer 1

Answer with explanation:

f(x)= | x-1 | +|1+x|, in the interval , -2 ≤x≤2.

     Breaking point of the given function are

    x-1=0→x=1

And, 1+x =0→ x= -1

So, when , x≥1

f(x)= x -1 +1+x=2 x

And, when ,-1≤ x < 1

f(x)= - (x-1)+1+x

    = -x +1+1+x

    = 2

Also, when , x < -1

f(x) = - (x-1)-(1+x)

     = -x +1 -1 -x

f(x)= -2 x

⇒When the function lies in the interval , -2 ≤ x < -1

f(x) = - 2 x

⇒In the interval, -1≤x<1

f(x)=2

⇒And, In the interval,1≤x≤2

f(x)=2 x

Answer 2

Answer:

See the photo

There is step by step explanation