Question

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

Answer 1

Answer:

We know, V = IR.  The potential difference V = 6V where the current is I.  

Resistance of circuit is  

R = 12 + 5 + 8 = 25 Ω.

Again I = V/R = 6/25 = 0.24 Ampere.  

Let the potential difference across 12 Ω resistor = V1; Current flowing is 0.24 Ampere.

Following Ohm’s law, we get V1=IR = 0.24 X 12= 2.88 volts.

So the ammeter will read 0.2r ampere and the voltmeter 2.88 volts.  

Answer 2

We know, V = IR.  The potential difference V = 6V where the current is I.  

Resistance of circuit is  

R = 12 + 5 + 8 = 25 Ω.

Again I = V/R = 6/25 = 0.24 Ampere.  

Let the potential difference across 12 Ω resistor = V1; Current flowing is 0.24 Ampere.

Following Ohm’s law, we get V1=IR = 0.24 X 12= 2.88 volts.

So the ammeter will read 0.2r ampere and the voltmeter 2.88 volts.