Reduce (1/1-4i-2/1+i)(3-4i/5+i) to standard form
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Answered by
4
Answer:
Step-by-step explanation:
(1-4i-2+1)(3-4i/5+i)
3-4i/5+i-12+16/5i^2-4i-6+8/5-2i+3i-4/5i^2+i
-6+3+4/5-16/5-1-4i/5+i-4i-12i+8i/5-2i+3i
-4-11/5+4i/5-20
(-20-11+4i-100i)/5
(-31-96i)/5
-1/5(31-96i)
Answered by
15
Answer :
Hence, the standard form is :
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