Question

reduce 8x^2y-8xy^2/x+xy​

Answer 1

Answer:

$8x {}^{2} y - \frac{8xy {}^{2} }{x} + x y \\ = \frac{8 {x}^{3} y -8x {y}^{2} + {x}^{2} y }{x} \\ = \frac{xy(8 {x}^{2} - 8y + x) }{x} \\ = y(8 {x}^{2} - 8y + x) \\ = 8 {x}^{2} y - 8 {y}^{2} + xy$

Answer 2

Answer:

$\bold\red{ <strong>★</strong><strong> </strong><strong>\</strong><strong>:</strong><strong>AnsWer</strong><strong> </strong>\:★:-}$

$8x {}^{2} y - \frac{8xy {}^{2} }{x} +xy$

$= \frac{8x {}^{3}y-8xy²+x²y }{x}$

$= \frac{xy(8x²-8y+x)}{x}$

$= y(8x {}^{2} - 8y \: + x)$

$= 8x {}^{2} y - 8y {}^{2} + xy$