Question

Reduce each of the following fraction to the lowest terms 256/612​ with formula​

Answer 1

Answer:

Observe the input parameters and what to be found:

Input values:

Fraction = 256/612

what to be found:

256/612 = ?

Find what is the lowest term of 256/612.

step 2

Find the prime factors of the numerator of given fraction 256/612.

Prime factors of 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

step 3

Find the prime factors of the denominator of given fraction 256/612.

Prime factors of 612 = 2 x 2 x 3 x 3 x 17

step 4

Rewrite the fraction 256/612 in the form of prime factors as like the below:

256

612

=(2 x 2 x 2 x 2 x 2 x 2 x 2 x 2)

(2 x 2 x 3 x 3 x 17)

step 5

Check and cancel the factors of 256 and 612 if any factors in the numerator and denominator can be cancelled each other in the above fraction of prime factors:

=(2 x 2 x 2 x 2 x 2 x 2 x 2 x 2)

(2 x 2 x 3 x 3 x 17)

=( 2 x 2 x 2 x 2 x 2 x 2)

( 3 x 3 x 17)

step 6

Simplify and rewrite the fraction as like the below:

=64

153

256

612

=64

153

Hence,

the simplest form of 256/612 is 64/153.