Question

Reduce excess 55 56 + 4
upon x square + 2 x + 1 lowest term

Answer 1

Answer:

hahahahahahahahahahah

Answer 2

$\red {\underline{\boxed {correct \: question}}}$

$\blue{reduce \: to \: lowest \: term }: \green{ \frac{ {x}^{2} + 4}{ {x}^{2} + 2x + 1 } }$

$\purple {\underline{\boxed {answer}}}$

$\pink{the \: lowest \: term} \: \: \orange { \frac{ {x}^{2}+ 4}{ {x}^{2} + 2x + 1 } } \: is$

$= \mathfrak\green{\frac{ {x}^{2} + {(2)}^{2} }{ {x}^{2} + x + x + 1 }}$

$= \frac{(x - 2)(x + 3)}{x(x + 1) + 1(x + 1)}$

$= \frac{(x - 2)(x + 3)}{(x + 1)(x + 1)}$

$<font color=purple>$

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