Question

Reduce the 5x+12y-22 = 0 into the intercept form and find their intercepts on the axis .

Answer 1

$\underline { \blue { Two \:intercepts \: form : }}$

$\pink { \frac{x}{a} + \frac{y}{b} = 1 }$

$Where, x - intercept = a ; \\y - intercept = b$

$Now, convert \: given \: Equation \\ 5x + 12y -2 2 = 0 \: above \:form , we \:get$

$\implies 5x + 12y = 22$

/* Divide each term by 22 ,we get */

$\implies \frac{5x}{22} + \frac{12y}{22} = \frac{22}{22}$

$\implies \frac{x}{\frac{22}{5}} + \frac{y}{\frac{22}{12}} = 1$

$\implies \frac{x}{\frac{22}{5}} + \frac{y}{\frac{11}{6}} = 1$

$x - intercept (a) = \frac{22}{5} \: and \\y - intercept (b) = \frac{11}{6}$

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