Question

reduce the Boolean expression (a+c)(a+d)(b+c)(b+d)​

Answer 1

Answer:

A.[B + C.(A.B + A.C')]

= A.[B + A.B.C + A.C'.C] [Distributive Law]

= A.[B + A.B.C + 0] [Complementary Law: C'.C = 0]

= A.[B(1 + AC)] [Distributive Law]

= A.B [∵ 1+AC=1]